How to remove compiler error with struct: “Use of unassigned local variable”

Question

The C# compiler is a bit ... old fashioned ... and won\'t do static analysis. So it breaks on seemingly correct code like this:

MyStruct s;
bool ini         


        

Answer 1

Is there a code way to tell it to shut up and mind its own business?

The compiler's business is implementing the C# specification. The code you've written should not compile according to the C# specification. The s.DoSomething() call is reachable without s being definitely assigned, therefore your code is broken. That's not the compiler's fault. If the Mono compiler used to allow it, that was a bug which has apparently now been fixed.

The simplest way of fixing it is to definitely assign the value, of course:

MyStruct s = new MyStruct(); // Value will never actually be used

There are plenty of cases where we (as humans) can tell that something will never happen, but the compiler can't. Here's another example:

public int Foo(int input)
{
    if (input >= 0)
    {
        return input;
    }
    else if (input < 0)
    {
        return -input;
    }
    // This is still reachable...
}

We know that every int input will go into one of those if bodies, but the compiler will still (correctly) give a compilation error on the above code, because the closing brace is reachable and it's a non-void method.

Your claim that "The code (should be) fully correct" is according to your reasoning, not the C# specificiation... and the compiler is only meant to care about the latter.

One thing to note: the specification doesn't even care about the fact that we do actually set inited to true in some cases. Even if it always had the value of false, it's still just a local variable, not a constant expression. Here's a simple example demonstrating that with no loop:

static void Main()
{
    int x;
    bool condition = false;
    if (condition)
    {
        Console.WriteLine(x);
    }
}

This still gives an error: "error CS0165: Use of unassigned local variable 'x'"

From section 8.7.1 of the C# 5 specification:

The first embedded statement of an if statement is reachable if the if statement is reachable and the boolean expression does not have the constant value false.

Here the expression is condition, which is a local variable. A local variable is not a constant expression in technical terms, even if it will never change. If you make it a local constant instead, it will compile:

static void Main()
{
    int x;
    const bool condition = false;
    if (condition)
    {
        Console.WriteLine(x);
    }
}

Now there's a warning about the body of the if statement being unreachable - but there's no error.