Why the infinite loop when data type is unsigned int?

Question

The below code runs perfectly.Gives the correct output but, the moment I change the sign of the variables from signed to unsigned the program runs into an infinite loop. The

Answer 1

As other answers already noted, the loop

for(i=count-1;i>=0;--i)

is an infinite loop if i is unsigned. It can be rewritten in a different form as

for (i = count - 1; i != -1; --i)

which will work as intended for both signed and unsigned i. However, some might find it less readable than the original.