Getting values of global stylesheet in jQuery

Question

When I use a style sheet definition like this on HTML page scope

#sideBar {
  float: left;
  width: 27.5%;
  min-width: 275;
  ... 
}

the f

Answer 1

Here is what I have done. Since all approaches did no really work reliable (cross browser etc.), I came across CSS parser/abstracter? How to convert stylesheet into object .

First I was about to use some fully blown CSS parsers such as

1. JSCSSP
2. jQuery CSS parser

which are powerful, but also heavyweight. Eventually I ended up with my own little function

// Get the original CSS values instead of values of the element.
// @param {String} ruleSelector
// @param {String} cssprop
// @returns {String} property of the style
exports.getCssStyle = function (ruleSelector, cssprop) {
    for (var c = 0, lenC = document.styleSheets.length; c < lenC; c++) {
        var rules = document.styleSheets[c].cssRules;
        for (var r = 0, lenR = rules.length; r < lenR; r++) {
            var rule = rules[r];
            if (rule.selectorText == ruleSelector && rule.style) {
                return rule.style[cssprop]; // rule.cssText;
            }
        }
    }
    return null;
};