What happens when float pointer is typecasted to char pointer?

Question

int main()
{
    float f = 12.2;
    char *p1;
    p1 = (char *)&f;
    printf (\"%d\", *p1);
}

This outputs 51.

Answer 1

1. You cast to (char) instead of (char*).
2. You print it out as integer.
3. Thus you get the least significant byte of f's address.

EDIT: According to the new markup you really truncate the float representation to its least significant byte (on little-endian machines)