Obtaining address of pointer in C with and without ampersand, what's the difference?

Question

I am having difficulty understanding this guide\'s code on pointers in C. I thought that you needed an ampersand to reference the address of a pointer, but the guide\'s code

Answer 1

you used

int var = 20;
int *ip;
ip = &var;

and you printed &var, ip, &ip *ip

Here &var and ip will indicate the address of the memory where 20 is saved. And *ip will indicate the value 20. And the most important thing what you wanted is &ip. When int *ip is called, the memory region for this variable will be created. so ip occupy some memory region. When you print &ip, then this will indicate the memory address where ip(contains the address of var) is saved.