scala - muliline string split

Question

I have this:

val msg = \"Preparado para cocinar...\"
val message = msg.splitAt(msg.length()/2)

println(message._1 + \"\\n\" + message._2.trim())
         


        

Answer 1

Another quite inelegant functional solution.

I'm pretty sure something better will come given some thought

Code

def divide(msg: String): (String, String) = {

  //index each letter
  val indexed = msg.zipWithIndex

  //split at first blank space after midpoint    
  val (fst, snd) = indexed span {case (c, i) => i < indexed.size/2 || c != ' '}

  //utility to recompose indexed parts
  def unzipString(s: Seq[(Char, Int)]) = s.map(_._1).mkString.trim

  //get separated lines    
  (unzipString(fst), unzipString(snd))
}

REPL

scala> val msg = "Parando para cocinar..."
msg: String = Parando para cocinar...

scala> val indexed = msg.zipWithIndex
indexed: scala.collection.immutable.IndexedSeq[(Char, Int)] = Vector((P,0), (a,1), (r,2), (a,3), (n,4), (d,5), (o,6), ( ,7), (p,8), (a,9), (r,10), (a,11), ( ,
12), (c,13), (o,14), (c,15), (i,16), (n,17), (a,18), (r,19), (.,20), (.,21), (.,22))

scala> val (fst, snd) = indexed span {case (c, i) => i < indexed.size/2 || c != ' '}
fst: scala.collection.immutable.IndexedSeq[(Char, Int)] = Vector((P,0), (a,1), (r,2), (a,3), (n,4), (d,5), (o,6), ( ,7), (p,8), (a,9), (r,10), (a,11))
snd: scala.collection.immutable.IndexedSeq[(Char, Int)] = Vector(( ,12), (c,13), (o,14), (c,15), (i,16), (n,17), (a,18), (r,19), (.,20), (.,21), (.,22))

scala> def unzipString(s: Seq[(Char, Int)]): String = s.map(_._1).mkString.trim
unzipString: (s: Seq[(Char, Int)])String

scala> (unzipString(fst), unzipString(snd))
res2: (String, String) = (Parando para,cocinar...)

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Updated: the original answer had a couple of blatantly obvious errors