Force invocation of base class method

Question

The following code when run obviously prints out \"B1/A2/B2\". Now, is it possible for it to print \"A1/A2/B2\" instead (i.e. A#method2() should invoke method1() on A, not

Answer 1

Yes, you can do it. Define A in package a:

package a;
public class A {
    void method1() {
        System.out.println("A1");
    }
    public void method2() {
        method1();
        System.out.println("A2");
    }
}

Define B in package b:

package b;
import a.A;
public class B extends A {
    @Override public void method2() {
        super.method2();
        System.out.println("B2");
    }
    void method1() {
        System.out.println("B1");
    }
}

Put your test in package a and run it. The result is A1/A2/B2. Of course this is unhealthy: note the necessary omission of @Override on method1 - if you put it back in, you will get a compiler error:

method does not override or implement a method from a supertype