In the set of double values, there is no such thing as the number 1.11 because internally, double uses a binary representation (as opposed to humans who are used to a decimal representation). Most finite decimal numbers (such as 1.11) have an infinite representation in binary, but since memory is limited, you lose some precision because of rounding.
The closest you can get to 1.11 with the double data type is 1.1100000000000000976996261670137755572795867919921875, which is internally represented as 0x3ff1c28f5c28f5c3.
Your requirement of two decimal places sounds like you are working with money. A simple solution is to store the cents in an integer (as opposed to the dollars in a double):
int cents = 111;
This way, you don't lose any precision. Another solution is to use a dedicated decimal data type.
