How do I convert a large binary String to byte array java?

Question

I have a large binary string \"101101110...\", and I am trying to store it into a byte array. what is the best way of doing it?

Lets say I have largeString = \"01001

Answer 1

Do it in a loop. Split the string at 8-character chunks and convert them separately. In "pseudocode" it's something like:

byte[] result = new byte[subs.size()];

int i = 0;
int j = 0;
while(i+8 <= s.length){
    result[j] = new Byte.valueOf(largeString.substring(i, i+8), 2);
    i+=8;
    j++;
}

result[j] = new Byte.valueOf(largeString.substring(i, largeString.length));