I want to check if, for example, the digit \'2\' is in 4059304593. My aim is to then check if there are any of the digits 1-9 not in my integer. This is what I have tried:>
You could convert your number to a string, then to a set to get the unique digits.
You just have to iterate over digits in 0-9 to find the ones not present in your original number :
>>> set(map(int,str(4059304593)))
set([0, 9, 3, 4, 5])
>>> digits = _
>>> [i for i in range(10) if i not in digits]
[1, 2, 6, 7, 8]