I want to check if, for example, the digit \'2\' is in 4059304593. My aim is to then check if there are any of the digits 1-9 not in my integer. This is what I have tried:>
This "digit" thing calls for a string approach, not a numeric one (reminds me of some Project Euler puzzles).
I'd create a set out of the digits of your number first (removing duplicates at the same time)
s = set(str(4059304593))
then to check for a digit:
print('2' in s)
(note that in for a set is performant)
then, to check whether s contains all the 013456789 digits:
print(s.issuperset("013456789"))
(if this must be done multiple times, it may be worth to create a set with the string, issuperset will work faster)