Effective [removed] Making your Constructor Function new-agnostic

Question

I\'ve been reading \'Effective JavaScript\' lately and I came across this question.

The author explains how it\'s important to make your Constructor Function new-ag

Answer 1

Why worry about 'this' and 'new' at all and why not always just create our constructors like the one above?

Because it is just more concise to write only

function Person(name, age) {
    this.name = name;
    this.age = age;
}

new was invented before Object.create (which is not available in older browsers) and became the standard pattern. Most people are so accustomed to it that they don't bother to include a if (!(this instanceof Person)) return new Person(name, age) check.

If you're setting up a new Object that does the same thing as 'this', can't we just never worry about if the constructor was called with new by foregoing 'this' and just creating the new object.

No, you don't always know how to create the new object. this instanceof Person is also true for anything else that does inherit from Person.prototype, and does allow for class inheritance:

function Employee(name, age, salary) {
    Person.call(this, name, age);
    this.salary = salary;
}
Employee.prototype = Object.create(Person.prototype);

The Person.call(this) wouldn't be possible if you chose to always return a new object.