Does the compiler continue evaluating an expression where all must be true if the first is false?

Question

I\'m sure this question has probably been answered before, so I apologize, but I wasn\'t able to find the proper search terms to find the answer.

Given the following

Answer 1

No. Both && and || are evaluated by short-circuit evaluation. This means that a && b returns false if a is false and a || b returns true if a is true and it will not evaluate b in either of these cases.

If for some reason you do not want short-circuit evaluation you can use the bitwise operators & and |.