Why does the “or” go before the “and”?

Question

int it=9, at=9;

if(it>4 || ++at>10 && it>0)  
{
    System.out.print(\"stuff\");    
}

System.out.print(at);

prints out stuff9 a

Answer 1

I feel I should add how to actually get your expected output.

Brief explanation: the || operator short-circuits the entire expression, thus the right side not even being evaluated.

But, to not short-circuit and get your expected output, instead of the || operator, just use |, like so:

int a = 9, b = 9;

if(a>4 | ++b>10 && a>0)  
{
    System.out.print("stuff");    
}
System.out.print(b);

The output to that is stuff10

This way, regardless of one side being true or not, they're both still evaluated.

The same thing goes for && and &