Replace whitespace outside quotes using regular expression

Question

Using C#, I need to prepare a search text for searching in a SQL Server database using the LIKE command by replacing all whitespace outside quotes with a % character. Exampl

Answer 1

It looks like you also want to remove the quotation marks and add a % to the beginning and end of the search string. Try this:

string s0 = @"my ""search text""";

Regex re = new Regex(@"(?x)
    (?:
       (?[^\s""]+)
     |
       ""(?[^""]+)""
    )
    (?:\s+|$)");

string s1 = @"%" + re.Replace(s0, @"${term}%");
Console.WriteLine(s1);

output:

%my%search text%