I have to following code snippet ...
Public Sub FindText(path As String, file As String) Dim Found As Range myText = \"test(\" MacroBook = Ac
As follow up from comments to the Q, Error 2015 occurs because your formula in the sheet returns #VALUE! error. You can handle it using IsError:
Error 2015
#VALUE!
IsError
If Not Found Is Nothing Then If Not IsError(Found) Then ' do sth End If End If