select * from users ORDER BY FIELD(status, \'A\', \'B\', \'C\', \'D\') ASC;
This will sort all the users according to their statuses such that all
to sort ASC -> status: 1
db.users.find().sort( { status: 1 } )
to sort DESC -> status: -1
db.users.find().sort( { status: -1 } )