Any concurrent.futures timeout that actually works?

Question

Tried to write a process-based timeout (sync) on the cheap, like this:

from concurrent.futures import ProcessPoolExecutor

def call_with_timeout(func, *args,         


        

Answer 1

You might want to take a look at pebble.

Its ProcessPool was designed to solve this exact issue: enable timeout and cancellation of running tasks without the need of shutting down the entire pool.

When a future times out or is cancelled, the worker gets actually terminated effectively stopping the execution of the scheduled function.

Timeout:

pool = pebble.ProcessPool(max_workers=1)
future = pool.schedule(func, args=args, timeout=1)
try:
    future.result()
except TimeoutError:
    print("Timeout")

Example:

def call_with_timeout(func, *args, timeout=3):
    pool = pebble.ProcessPool(max_workers=1)
    with pool:
        future = pool.schedule(func, args=args, timeout=timeout)
        return future.result()