Evaluation of C expression

Question

int main() {
  int i = -3, j = 2,  k = 0, m;
  m = ++i || ++j && ++k;
  printf(\"%d %d %d %d\\n\", i, j, k, m);
  return 0;
}

i thought tha

Answer 1

m = ++i || ++j && ++k;

Since && has higher precedence than || so the expression is interpreted as ++i || (++j && ++k)

|| is short circuiting and so right hand operand of || operator doesn't get evaluated because ++i returns a non zero value.