Evaluation of C expression

Question

int main() {
  int i = -3, j = 2,  k = 0, m;
  m = ++i || ++j && ++k;
  printf(\"%d %d %d %d\\n\", i, j, k, m);
  return 0;
}

i thought tha

Answer 1

&& and || use short-circuit evaluation, i.e. in the expression a&&b a is evaluated first, if it is false then the whole expression is false and b is not evaluated. In a||b if a is true then b is not evaluated. Note that if you overload && or || short-circuit rules will no longer apply. HTH