Evaluation of C expression

Question

int main() {
  int i = -3, j = 2,  k = 0, m;
  m = ++i || ++j && ++k;
  printf(\"%d %d %d %d\\n\", i, j, k, m);
  return 0;
}

i thought tha

Answer 1

&& does have higher precedence than ||, which means that ++i || ++j && ++k parses as ++i || (++j && ++k).

However this does not change the fact that the RHS of || only executes if the LHS returns 0.

Precedence does not affect order of evaluation.