C# - What is the reason for “Explicitly implemented interface members are always implicitly private ?”

Question

When i need to implement the interface member explicitly ,it is private.

for example :

 // when explicit implementation it is always private
  void I         


        

Answer 1

Because you are saying when my object is an IPointy than you can call the IPointy method draw. Otherwise no.

 public interface IPointy
{
    void Draw();
}

public class PointyImplementer : IPointy
{
    #region IPointy Members

    void IPointy.Draw()
    {
        Console.WriteLine("You have drawn");
    }

    #endregion
}

class Program
{
    static void Main(string[] args)
    {
        IPointy pi = new PointyImplementer();

        pi.Draw();

        Console.Read();
    }
}

It is a way for you to mask the interface you are implementing.