Is there any way of matching a regex from right to left? What Im looking for is a regex that gets
MODULE WAS INSERTED EVENT
LOST SIGNAL ON E1/T
Does the input file fit nicely into fixed width tabular text like this? Because if it does, then the simplest solution is to just take the right substring of each line, from column 56 to column 94.
In Unix, you can use the cut command:
cut -c56-94 yourfile
In Java, you can write something like this:
String[] lines = {
"CLI MUX trap received: (022) CL-B MCL-2ETH MODULE WAS INSERTED EVENT 07-05-2010 12:08:40",
"CLI MUX trap received: (090) IO-2 ML-1E1 EX1 LOST SIGNAL ON E1/T1 LINK OFF 04-06-2010 09:58:58",
"CLI MUX trap received: (094) IO-2 ML-1E1 EX1 CRC ERROR EVENT 04-06-2010 09:58:59",
"CLI MUX trap received: (009) CLK IS DIFF FROM MASTER CLK SRC OFF 07-05-2010 12:07:32",
};
for (String line : lines) {
System.out.println(line.substring(56, 94));
}
This prints:
MODULE WAS INSERTED EVENT
LOST SIGNAL ON E1/T1 LINK OFF
CRC ERROR EVENT
CLK IS DIFF FROM MASTER CLK SRC OFF
This is most likely not necessary, but something like this works (as seen on ideone.com):
line.replaceAll(".* \\b(.+ .+) \\S+ \\S+", "$1")
As you can see, it's not very readable, and you have to know your regex to really understand what's going on.
Essentially you match this to each line:
.* \b(.+ .+) \S+ \S+
And you replace it with whatever group 1 matched. This relies on the usage of two consecutive spaces exclusively for separating the columns in this table.