sort a dictionary (or whatever key-value data structure in js) on word_number keys efficiently

Question

how do I sort a dictionary by key like

dict[\"word_21\"] = \"Hello Java\";
dict[\"word_22\"] = \"Hello World\";
dict[\"word_11\"] = \"Hello Javascript\";
         


        

Answer 1

If you just want to sort keys in an object, the following is fine (its a one liner)

/**
 * (typescript) returns the given object with keys sorted alphanumerically.
 * @param {T} obj the object to sort
 * @returns {T} the sorted object
 */
 const sort = (obj: T): T => Object.keys(obj).sort()
        .reduce((acc, c) => { acc[c] = obj[c]; return acc }, {}) as T

or the same in javascript

/**
 * (javascript) returns the given object with keys sorted alphanumerically.
 * @param {T} obj the object to sort
 * @returns {T} the sorted object
 */
 const sort = (obj) => Object.keys(obj).sort()
        .reduce((acc, c) => { acc[c] = obj[c]; return acc }, {})