Printing an ASCII diamond with set width in python

Question

Yes, this is a homework task. But just please, if you\'re going to give me the code please tell me what you\'ve done in detail. I am extremely new to this.

So the ta

Answer 1

 i=1
 j=input("ENTER NO =")
 l=0
 for i in range(i,j-((j/2)-1),1):
     print (' ' * ((j+1)/2-i)+'*' *(i*2-1))
     l=(j/2+1)
     while  (i==l):
        i=1
        for i in range(i,j,1):
            print (' ' *((i*2)-i)+'*' *(j-i*2))
        if [i==j-1]:
            l=raw_input('')