Byte precision pointer arithmetic in C when sizeof(char) != 1

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悲哀的现实
悲哀的现实 2020-12-11 13:07

How can one portably perform pointer arithmetic with single byte precision?

Keep in mind that:

  • char is not 1 byte on all platforms
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  •  醉话见心
    2020-12-11 13:09

    Your assumption is flawed - sizeof(char) is defined to be 1 everywhere.

    From the C99 standard (TC3), in section 6.5.3.4 ("The sizeof operator"):

    (paragraph 2)

    The sizeof operator yields the size (in bytes) of its operand, which may be an expression or the parenthesized name of a type.

    (paragraph 3)

    When applied to an operand that has type char, unsigned char, or signed char, (or a qualified version thereof) the result is 1.

    When these are taken together, it becomes clear that in C, whatever size a char is, that size is a "byte" (even if that's more than 8 bits, on some given platform).

    A char is therefore the smallest addressable type. If you need to address in units smaller than a char, your only choice is to read a char at a time and use bitwise operators to mask out the parts of the char that you want.

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