Golang channel output order

Question

func main() {
  messages := make(chan string)
  go func() { messages <- \"hello\" }()
  go func() { messages <- \"ping\" }()
  msg := <-messages
  msg2 := &         


        

Answer 1

In Golang Spec Channels order is described as:-

Channels act as first-in-first-out queues. For example, if one goroutine sends values on a channel and a second goroutine receives them, the values are received in the order sent.

It will prints which value is available first to be received on other end. If you wants to synchronize them use different channels or add wait Groups.

package main

import (
    "fmt"
)

func main() {
  messages1 := make(chan string)
  messages2 := make(chan string)
  go func(<-chan string) {
        messages2 <- "ping" 
    }(messages2)
  go func(<-chan string) {
        messages1 <- "hello" 
    }(messages1)
  fmt.Println(<-messages1)
  fmt.Println(<-messages2)
}

If you see you can easily receive any value you want according to your choice using different channels.

Go playground