How not to stop the execution of other function in python in case of Exception/Error

Question

I have a script in python which works as shown below. Each function performs a completely different task and not related to each other. My problem is if function2()<

Answer 1

No need to write multiple try/except. Create a list of your function and execute them. For example, you code should be like:

if __name__ == '__main__':
    func_list = [function1, function2, function3, function4, function5]

    for my_func in func_list:
        try:
            my_func()
        except:
            pass

---

OR, create a decorator and add that decorator to each of your function. Check A guide to Python's function decorators. For example, your decorator should be like:

def wrap_error(func):
    def func_wrapper(*args, **kwargs):
        try:
           return func(*args, **kwargs)
        except:
           pass
    return func_wrapper

Now add this decorator with your function definition as:

@wrap_error
def function1():
    some code

Functions having this decorator added to them won't raise any Exception