return reference to local variable [duplicate]

Answer 1

Normally you use * to declare a pointer variable and also to dereference the pointer back to the original variable afterwords. & returns the address from a variable

I haven't tested this, but does the following work any better?

#include 
using namespace std;

double* GetSomeData()
{
  double h = 46.50;
  return &h;
}

int main()
{
  double nonRef = GetSomeData();
  double* ref = GetSomeData();
  cout << "nonRef: " << nonRef << endl;
  cout << "ref: " << *ref << endl;
  return 0;
}