Parallel computing — jumbled up output?

Question

I\'m trying to learn the basics of parallel computing, but I\'m running into an issue on my computer. Take a look at my code below. Basically, I want to print out the line &

Answer 1

As already explained, the assumption that printf() is atomic and won't mangle your output whereas std::cout::operator<<() is not and will mess things up if fundamentally wrong.

However, there is still a (tiny) part of "truth" in this, but at a different level. Let me give you an example:

If I try an OpenMP "Hello world" C-style, that might give this:

printf( "Hello from thread %d of %d\n",
         omp_get_thread_num(),
         omp_get_num_threads() );

The same one C++-style could look like this:

std::cout << "Hello from thread " << omp_get_thread_num()
          << " of " << omp_get_num_threads()
          << std::endl;

And the essential difference between the two is that for printf(), I only call the printing method once, with a fully prepared output string, while the C++-style one will call std::cout::operator<<() 5 times, with only bits and pieces of lines that may or may not be sent to the standard output. Internally, anything can happen and I won't try to commit on any sort of behaviour. But at least by using printf() here, I increase my chances of a clean output, even if I cannot guaranty it.

Here is a full example:

#include 
#include 
#include 

int main() {
    #pragma omp parallel
    printf( "Hello from thread %d of %d with printf()\n",
             omp_get_thread_num(),
             omp_get_num_threads() );

    printf( "*** outside of parallel region ***\n" );

    #pragma omp parallel
    std::cout << "Hello from thread " << omp_get_thread_num()
              << " of " << omp_get_num_threads()
              << " with std::cout"
              << std::endl;
    return 0;
}

Which on my Linux laptop gives me (GCC 5.2):

~/tmp$ g++ -fopenmp stdout.cc
~/tmp$ ./a.out 
Hello from thread 3 of 4 with printf()
Hello from thread 0 of 4 with printf()
Hello from thread 2 of 4 with printf()
Hello from thread 1 of 4 with printf()
*** outside of parallel region ***
Hello from thread Hello from thread Hello from thread Hello from thread 1 of 4 with std::cout23 of 4 with std::cout
 of 4 with std::cout
0 of 4 with std::cout

~/tmp$

If you look carefully, you can see that none of the individual calls to std::cout::operator<<() is split, but each new call is an opportunity for the various threads to races each-other, and to get the output mangled.

So again, telling that printf() is atomic and won't mess things up is wrong, but simply, for a complex output string, it is less likely to be mangled than with std::cout.