printf just before a delay doesn't work in C

Question

Does anyone know why if i put a printf just before a delay it waits until the delay is finished before it prints de message?

Code1 with sleep():

int          


        

Answer 1

Normally, standard output is buffered until you either:

• output a \n character
• call fflush(stdout)

Do one of these things before calling delay() and you should see your output.