POSIX shared memory and semaphores permissions set incorrectly by open calls

Question

I\'m trying to create a shared memory which will be used by several processes, which will not necessarily be started by the same user, so I create the segment with the follo

Answer 1

It's probably umask.

Citing the manpage of shm_open:

   O_CREAT    Create  the  shared memory object if it does not exist.  The user and
              group ownership of the object are taken from the corresponding effec‐
              tive IDs of the calling process, and the object's permission bits are
              set according to the low-order 9 bits of mode, except that those bits
              set in the process file mode creation mask (see umask(2)) are cleared
              for the new object.  A set of macro constants which can  be  used  to
              define  mode  is  listed  in open(2).  (Symbolic definitions of these
              constants can be obtained by including .)

So, in order to allow creating files which are world-writable, you'd need to set an umask permitting it, for example:

umask(0);

Set like this, umask won't affect any permissions on created files anymore. However, you should note that if you will then create another file without specifying permissions explicitly, it will be world-writable as well.

Thus, you may want to clear the umask only temporarily, and then restore it:

#include 
#include 

...

void yourfunc()
{
    // store old
    mode_t old_umask = umask(0);

    int fd = shm_open(SHARE_MEM_NAME,O_RDWR | O_CREAT,0606);

    // restore old
    umask(old_umask);
}