Updating pointers in a function

Question

I am passing a pointer a function that updates it. However when the function returns the pointer it returns to the value it had prior to the function call.

Here is m

Answer 1

When you give a pointer to a function, you have a copy of the reference value that you originally had.

Then, if you modify your pointer, you're modifying a copy.

If you want to update the original one, you need to pass it with a double pointer ** which will let you modify the original pointer, passing a "reference to a reference" (double pointer).