PHP swear word filter

Question

I\'m working on a WordPress plugin that replaces the bad words from the comments with random new ones from a list.

I now have 2 arrays: one containing the bad words

Answer 1

I came up to this method and it's working fine. Returning true, in case there is an entry of bad words in the entry.

Example:

function badWordsFilter($inputWord) {
  $badWords = Array("bad","words","here");
  for($i=0;$i

Usage:

if (badWordsFilter("bad")) {
    echo "Bad word was found";
} else {
    echo "No bad words detected";
}

As the word 'bad' is blacklisted it will echo.

Online example 1

EDIT 1:

As offered by rid it's also possible to do simple in_array check:

function badWordsFilter($inputWord) {
  $badWords = Array("bad","words","here");
     if(in_array(strtolower($inputWord), $badWords) ) {
        return true;
     }
  return false;
}

Online example 2

EDIT 2:

As I promised, I came up to the slightly different idea of replacing bad words with good words, as you mentioned in your question. I hope it will help you a bit but this is the best I can offer at the moment, as I'm totally not sure on what you're trying to do.

Example:

1. Let's combine an array with bad and good words into one

$wordsTransform = array(
  'shit' => 'ship'
);

2. Your imaginary user input

$string = "Rolling In The Deep by Adel\n
\n
There's a fire starting in my heart\n
Reaching a fever pitch, and it's bringing me out the dark\n
Finally I can see you crystal clear\n
Go ahead and sell me out and I'll lay your shit bare";

3. Replacing bad words with good words

$string = strtr($string, $wordsTransform);

4. Getting the desired output

Rolling In The Deep

There's a fire starting in my heart
Reaching a fever pitch, and it's bringing me out the dark
Finally I can see you crystal clear
Go ahead and sell me out and I'll lay your ship bare

Online example 3

EDIT 3:

To follow the correct comment from Wrikken, I have totally forgotten about that strtr is case sensitive and that it's better to follow word-boundary. I have borrowed the following example from
PHP: strtr - Manual and modified it slightly.

Same idea as in my second edit but not register dependent, it checks for word boundaries and puts a backslash in front of every character that is part of the regular expression syntax:

1. Method:

//
// Written by Patrick Rauchfuss
class String
{
    public static function stritr(&$string, $from, $to = NULL)
    {
        if(is_string($from))
            $string = preg_replace("/\b{$from}\b/i", $to, $string);

        else if(is_array($from))
        {
            foreach ($from as $key => $val)
                self::stritr($string, $key, $val);
        }
        return preg_quote($string); // return and add a backslash to special characters
    }
}

2. An array with bad and good words

$wordsTransform = array(
            'shit' => 'ship'
        );

3. Replacement

String::stritr($string, $wordsTransform);

Online example 4