C++: getting the row size of a multidimensional array passed to a function

Question

I\'m trying to write a function that will print out the contents of a multidimensional array. I know the size of the columns, but not the size of the rows.

EDIT: Sin

Answer 1

You can get the size of both arrays with some template magic:

template< typename T, std::size_t n, std::size_t m >
void foo( T(&)[n][m] ) {
  std::cout << n << " " << m << std::endl;
}     

int main() {
  int a[3][3];
  int b[2][5];

  foo(a); foo(b);
}

This only works for arrays whose bounds are known at compile time and not for dynamically allocated arrays.

In any case: You should use std::vector or boost::multiarray.