Little vs Big Endianess: How to interpret the test

Question

So I\'m writing a program to test the endianess of a machine and print it. I understand the difference between little and big endian, however, from what I\'ve found online,

Answer 1

Yes, that answers the question. Here's a more general answer:

#include 
#include   
#include 

using namespace std;

int main()
{
cout<<"sizeof(char) = "<

This displays 8 4 2 1 for the dereferenced values at c, c+1, c+2, and c+3 respectively. The sum y is 16909320, which is equal to x. Even though the significance of the digits grow from right-to-left, this is still Little Endian because the corresponding memory values also grow from right-to-left, which is why the left-shift binary operator << would increase a variable's value until non-zero digits are shifted off the variable altogether. Don't confuse this operator with std::cout's << operator. If this were Big Endian, then the display for c, c+1, c+2, and c+3 respectively would look like: 1 2 4 8