How to compare array to a number for if statement?

Question

H0 is an array ([1:10]), and H is a single number (5).

How to compare every element in H0 with the s

Answer 1

if requires the following statement to evaluate to a scalar true/false. If the statement is an array, the behaviour is equivalent to wrapping it in all(..).

If your comparison results in a logical array, such as

H0  = 1:10;
H   = 5;
test = H0>H;

you have two options to pass test through the if-statement:

(1) You can aggregate the output of test, for example you want the if-clause to be executed when any or all of the elements in test are true, e.g.

if any(test)
  do something
end

(2) You iterate through the elements of test, and react accordingly

for ii = 1:length(test)
   if test(ii)
      do something
   end
end

Note that it may be possible to vectorize this operation by using the logical vector test as index.

edit

If, as indicated in a comment, you want P(i)=H0(i)^3 if H0(i), and otherwise P(i)=H0(i)^2, you simply write

 P = H0 .^ (H0