int does not override Integer in Java

Question

I had a function in Java with method signature

public void myMethod (int someInt, String someString) 

in my abstract class and I had over-

Answer 1

They are absolutely not overridden but overload since the parameters are different. And JVM will choose the method to launch base on this: widen - boxing - var args...

For example, you have three methods

void add(long n) {} // call this method 1
void add(int... n) {} // call this method 2
void add(Integer n) {} // call this method 3

and when you invoke:

int a = 5;
add(a);

the method 1 will be invoked.