Overloading with Short and int

Question

Why this code will print int?

public static void main(String[] args) {
    short s = 5;
    A(s);
}
public static void A(int a){
    System.out.println(\"int         


        

Answer 1

Because widening beats boxing

Reason:

Because widening was there long long before where boxing was introduced later on so not to break any code it does this.