Why is this constexpr static member function not seen as constexpr when called?

Question

Why is this constexpr static member function, identified by the //! Nah comment, not seen as constexpr when called?

Answer 1

From memory, member function bodies are evaluated only once the class has been completely defined.

static constexpr int bah = static_n_items(); 

forms part of the class definition, but it's referring to a (static) member function, which cannot yet be defined.

Solution:

defer constant expressions to a base class and derive from it.

e.g.:

struct Item_id_base
{
    enum Enum
    {
        size, position, attributes, window_rect, max_window_size, _
    };

    static constexpr int n_items_ = _;                          // OK
    constexpr auto member_n_items() const -> int { return _; }  // OK
    static constexpr auto static_n_items() -> int { return _; } // OK
    static constexpr int so_far = n_items_;                     // OK
};

struct Item_id : Item_id_base
{
    #ifndef OUT_OF_CLASS
        static constexpr int bah = static_n_items();            // now OK
    #endif
};

constexpr auto n_ids() -> int { return Item_id().member_n_items(); }    // OK

auto main() -> int
{
    #ifdef OUT_OF_CLASS
        static constexpr int bah = Item_id::static_n_items();   // OK
    #endif
}

Why do you think the standard disallows it?

Because this is illegal:

struct Item_id
{   
    // ... etc.

    #ifndef OUT_OF_CLASS
        static constexpr int bah;// = static_n_items();            //! Nah.
    #endif
};

constexpr int Item_id::bah = static_n_items();

And a constexpr must have a constexpr definition. The only place we can define it is during its declaration...

... so by deduction it cannot refer to any function who's body is not yet defined.

I am at a loss to know where to look in the standard for all that. Probably 5 different, seemingly unrelated clauses :)