How to portably find out min(INT_MAX, abs(INT_MIN))?

Question

How can I portably find out the smallest of INT_MAX and abs(INT_MIN)? (That\'s the mathematical absolute value of INT_MIN, not a call

Answer 1

abs(INT_MIN) will invoke undefined behavior. Standard says

7.22.6.1 The abs, labs and llabs functions:

The abs, labs, and llabs functions compute the absolute value of an integer j. If the result cannot be represented, the behavior is undefined.

Try this instead :
Convert INT_MIN to unsignrd int. Since -ve numbers can't be represented as an unsigned int, INT_MAX will be converted to UINT_MAX + 1 + INT_MIN.

#include 
#include 

unsigned min(unsigned a, unsigned b)
{
    return a < b ? a : b;
}

int main(void)
{
    printf("%u\n", min(INT_MAX, INT_MIN));
}