How to portably find out min(INT_MAX, abs(INT_MIN))?

Question

How can I portably find out the smallest of INT_MAX and abs(INT_MIN)? (That\'s the mathematical absolute value of INT_MIN, not a call

Answer 1

-INT_MAX is representable as an int in all C and C++ dialects, as far as I know. Therefore:

-INT_MAX <= INT_MIN ? -INT_MIN : INT_MAX