Find the directory part (minus the filename) of a full path in access 97

Question

For various reasons, I\'m stuck in Access 97 and need to get only the path part of a full pathname.

For example, the name

c:\\whatever dir\\another d         


        

Answer 1

Use these codes and enjoy it.

Public Function GetDirectoryName(ByVal source As String) As String()
Dim fso, oFolder, oSubfolder, oFile, queue As Collection
Set fso = CreateObject("Scripting.FileSystemObject")
Set queue = New Collection

Dim source_file() As String
Dim i As Integer        

queue.Add fso.GetFolder(source) 'obviously replace

Do While queue.Count > 0
    Set oFolder = queue(1)
    queue.Remove 1 'dequeue
    '...insert any folder processing code here...
    For Each oSubfolder In oFolder.SubFolders
        queue.Add oSubfolder 'enqueue
    Next oSubfolder
    For Each oFile In oFolder.Files
        '...insert any file processing code here...
        'Debug.Print oFile
        i = i + 1
        ReDim Preserve source_file(i)
        source_file(i) = oFile
    Next oFile
Loop
GetDirectoryName = source_file
End Function

And here you can call function:

Sub test()
Dim s
For Each s In GetDirectoryName("C:\New folder")
Debug.Print s
Next
End Sub