Find the directory part (minus the filename) of a full path in access 97

Question

For various reasons, I\'m stuck in Access 97 and need to get only the path part of a full pathname.

For example, the name

c:\\whatever dir\\another d         


        

Answer 1

vFilename="C:\Informes\Indicadores\Program\Ind_Cont_PRv.txt"

vDirFile = Replace(vFilename, Dir(vFileName, vbDirectory), "")

' Result=C:\Informes\Indicadores_Contraloria\Programa\Versiones anteriores\