Find the directory part (minus the filename) of a full path in access 97

Question

For various reasons, I\'m stuck in Access 97 and need to get only the path part of a full pathname.

For example, the name

c:\\whatever dir\\another d         


        

Answer 1

left(currentdb.Name,instr(1,currentdb.Name,dir(currentdb.Name))-1)

The Dir function will return only the file portion of the full path. Currentdb.Name is used here, but it could be any full path string.