Find the directory part (minus the filename) of a full path in access 97

Question

For various reasons, I\'m stuck in Access 97 and need to get only the path part of a full pathname.

For example, the name

c:\\whatever dir\\another d         


        

Answer 1

I always used the FileSystemObject for this sort of thing. Here's a little wrapper function I used. Be sure to reference the Microsoft Scripting Runtime.

Function StripFilename(sPathFile As String) As String

'given a full path and file, strip the filename off the end and return the path

Dim filesystem As New FileSystemObject

StripFilename = filesystem.GetParentFolderName(sPathFile) & "\"

Exit Function

End Function