Find the directory part (minus the filename) of a full path in access 97

Question

For various reasons, I\'m stuck in Access 97 and need to get only the path part of a full pathname.

For example, the name

c:\\whatever dir\\another d         


        

Answer 1

You can do something simple like: Left(path, InStrRev(path, "\"))

Example:

Function GetDirectory(path)
   GetDirectory = Left(path, InStrRev(path, Application.PathSeparator))
End Function