How to use DATEDIFF to return year, month and day?

Question

How can I use DATEDIFF to return the difference between two dates in years, months and days in SQL Server 2005

DATEDIFF (date , dat         


        

Answer 1

TL;DR approximates years & months without having to create a function.

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I found this question searching for "get years months from datediff". I was looking for something a bit quicker (and yeah, probably dirtier) than the above function-creating solutions.

I came up with the following in-line sql which approximates the years and months. Sufficient for my own purposes, which is getting a count of events grouped by user's rough age at the time.

select cast(datediff(event_datetime, dateofbirth)/365.25 as unsigned) as years, 
       cast((mod(datediff(event_datetime, dateofbirth),365.25))/30.4375 as unsigned) as months
from tablename
;