How to use DATEDIFF to return year, month and day?

Question

How can I use DATEDIFF to return the difference between two dates in years, months and days in SQL Server 2005

DATEDIFF (date , dat         


        

Answer 1

Using ParseName

DECLARE
  @ReportBeginDate DATE

SET @ReportBeginDate='2015-01-01';

IF OBJECT_ID('TEMPDB..#tmp_ymd') IS NOT NULL
BEGIN
DROP TABLE #tmp_ymd;
END;

select
cast(cast(datediff(mm,@ReportBeginDate,getdate()) as decimal (10,2))/12 as decimal(10,2)) as YearMonthDec
,cast(datediff(dd,@ReportBeginDate,getdate()) as decimal (10,2)) as DayDec
into #tmp_ymd

select
YearMonthDec
,cast(parsename(YearMonthDec,2) as decimal (10,0)) as yearnum
,cast(cast(parsename(YearMonthDec,1) as decimal (10,0))/100*(12) as numeric) as monthnum
,case when YearMonthDec>=1 then datediff(dd,CONVERT(VARCHAR(25),DATEADD(dd,-(DAY(getdate())-1),getdate()),101),getdate()) else DayDec end as daynum

from #tmp_ymd