Simplest Way To Do Dynamic View Models in ASP.NET MVC 3

Question

Caveat: This might be an inappropriate use of C#\'s dynamic keyword and I probably should be using a strongly-typed view model, but...

I\'m trying t

Answer 1

Ok, you could do the following, but I wouldn't recommend it. Create a static method similar to the following

public static IHtmlString DisplayProperty(object obj, string property) {
    return new HtmlString(TypeDescriptor.GetProperties(obj)[property].GetValue(obj).ToString());
}

Then in your cshtml file make the following call (make sure to using your proper namespace)

    @foreach (var item in Model) {
    
        @DisplayProperty(x, "RateCodeName")
        @DisplayProperty(x, "Year")                            
        @DisplayProperty(x, "Rate")
        >@DisplayProperty(x, "Comment")
    
    }

I wouldn't recommend this though but it is a solution to your problem that doesn't require a model.